K^4+3k^2-28=0

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Solution for K^4+3k^2-28=0 equation: 



^4+3K^2-28=0

We add all the numbers together, and all the variables

3K^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$K=\frac{-b}{2a}=\frac{0}{6}=0$

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